3x^2-70x-600=0

Solution for 3x^2-70x-600=0 equation:

3x^2-70x-600=0

a = 3; b = -70; c = -600;
Δ = b2-4ac
Δ = -702-4·3·(-600)
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12100}=110$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-110}{2*3}=\frac{-40}{6}
=-6+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+110}{2*3}=\frac{180}{6}
=30
$